(16-3y)*y=4

Solution for (16-3y)*y=4 equation:

(16-3y)*y=4

We move all terms to the left:

(16-3y)*y-(4)=0

We add all the numbers together, and all the variables

(-3y+16)*y-4=0

We multiply parentheses

-3y^2+16y-4=0

a = -3; b = 16; c = -4;
Δ = b2-4ac
Δ = 162-4·(-3)·(-4)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{13}}{2*-3}=\frac{-16-4\sqrt{13}}{-6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{13}}{2*-3}=\frac{-16+4\sqrt{13}}{-6}
$