(16+2x)(30+2x)=1472

Solution for (16+2x)(30+2x)=1472 equation:

(16+2x)(30+2x)=1472

We move all terms to the left:

(16+2x)(30+2x)-(1472)=0

We add all the numbers together, and all the variables

(2x+16)(2x+30)-1472=0

We multiply parentheses ..

(+4x^2+60x+32x+480)-1472=0

We get rid of parentheses

4x^2+60x+32x+480-1472=0

We add all the numbers together, and all the variables

4x^2+92x-992=0

a = 4; b = 92; c = -992;
Δ = b2-4ac
Δ = 922-4·4·(-992)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-156}{2*4}=\frac{-248}{8}
=-31
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+156}{2*4}=\frac{64}{8}
=8
$