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(15x-3=10x+7)
We move all terms to the left:
(15x-3-(10x+7))=0
We calculate terms in parentheses: +(15x-3-(10x+7)), so:We get rid of parentheses
15x-3-(10x+7)
determiningTheFunctionDomain 15x-(10x+7)-3
We get rid of parentheses
15x-10x-7-3
We add all the numbers together, and all the variables
5x-10
Back to the equation:
+(5x-10)
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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