(15x-25)(4x+63)=

Solution for (15x-25)(4x+63)= equation:

(15x-25)(4x+63)=

We move all terms to the left:

(15x-25)(4x+63)-()=0

We add all the numbers together, and all the variables

(15x-25)(4x+63)=0

We multiply parentheses ..

(+60x^2+945x-100x-1575)=0

We get rid of parentheses

60x^2+945x-100x-1575=0

We add all the numbers together, and all the variables

60x^2+845x-1575=0

a = 60; b = 845; c = -1575;
Δ = b2-4ac
Δ = 8452-4·60·(-1575)
Δ = 1092025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1092025}=1045$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(845)-1045}{2*60}=\frac{-1890}{120}
=-15+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(845)+1045}{2*60}=\frac{200}{120}
=1+2/3
$