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(15x+30)=1/3(102-12x)
We move all terms to the left:
(15x+30)-(1/3(102-12x))=0
Domain of the equation: 3(102-12x))!=0We add all the numbers together, and all the variables
x∈R
(15x+30)-(1/3(-12x+102))=0
We get rid of parentheses
15x-(1/3(-12x+102))+30=0
We multiply all the terms by the denominator
15x*3(-12x+102))-(1+30*3(-12x+102))=0
Wy multiply elements
45x^2(-+90x(-=0
We use the square of the difference formula
45x^2(-90x(-=0
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