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(15x+10)(6x+2)=180
We move all terms to the left:
(15x+10)(6x+2)-(180)=0
We multiply parentheses ..
(+90x^2+30x+60x+20)-180=0
We get rid of parentheses
90x^2+30x+60x+20-180=0
We add all the numbers together, and all the variables
90x^2+90x-160=0
a = 90; b = 90; c = -160;
Δ = b2-4ac
Δ = 902-4·90·(-160)
Δ = 65700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{65700}=\sqrt{900*73}=\sqrt{900}*\sqrt{73}=30\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-30\sqrt{73}}{2*90}=\frac{-90-30\sqrt{73}}{180} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+30\sqrt{73}}{2*90}=\frac{-90+30\sqrt{73}}{180} $
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