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(15/y)+(9/y)=3
We move all terms to the left:
(15/y)+(9/y)-(3)=0
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+15/y)+(+9/y)-3=0
We get rid of parentheses
15/y+9/y-3=0
We multiply all the terms by the denominator
-3*y+15+9=0
We add all the numbers together, and all the variables
-3y+24=0
We move all terms containing y to the left, all other terms to the right
-3y=-24
y=-24/-3
y=+8
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