(15/x)+(9x-7/x+2)=3

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Solution for (15/x)+(9x-7/x+2)=3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

9*x+15/x-(7/x)+2 = 3 // - 3

9*x+15/x-(7/x)-3+2 = 0

9*x+15/x-7*x^-1-3+2 = 0

9*x^1+8*x^-1-1*x^0 = 0

(9*x^2-1*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(9*x^2-1*x^1+8*x^0) = 0

x^1

9*x^2-x+8 = 0

9*x^2-x+8 = 0

DELTA = (-1)^2-(4*8*9)

DELTA = -287

DELTA < 0

x in { } 

x belongs to the empty set

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