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(15-x)x-2=14
We move all terms to the left:
(15-x)x-2-(14)=0
We add all the numbers together, and all the variables
(-1x+15)x-2-14=0
We add all the numbers together, and all the variables
(-1x+15)x-16=0
We multiply parentheses
-1x^2+15x-16=0
a = -1; b = 15; c = -16;
Δ = b2-4ac
Δ = 152-4·(-1)·(-16)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{161}}{2*-1}=\frac{-15-\sqrt{161}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{161}}{2*-1}=\frac{-15+\sqrt{161}}{-2} $
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