(15-x)(20+x)=(30-x)(5+x)

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Solution for (15-x)(20+x)=(30-x)(5+x) equation: 



(15-x)(20+x)=(30-x)(5+x)

We move all terms to the left:

(15-x)(20+x)-((30-x)(5+x))=0

We add all the numbers together, and all the variables

(-1x+15)(x+20)-((-1x+30)(x+5))=0

We multiply parentheses ..

(-1x^2-20x+15x+300)-((-1x+30)(x+5))=0



We calculate terms in parentheses: -((-1x+30)(x+5)), so:

(-1x+30)(x+5)

We multiply parentheses ..

(-1x^2-5x+30x+150)

We get rid of parentheses

-1x^2-5x+30x+150

We add all the numbers together, and all the variables

-1x^2+25x+150

Back to the equation:

-(-1x^2+25x+150)



We get rid of parentheses

-1x^2+1x^2-20x+15x-25x+300-150=0

We add all the numbers together, and all the variables

-30x+150=0

We move all terms containing x to the left, all other terms to the right

-30x=-150

x=-150/-30

x=+5

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