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(15+x/5+x)=2
We move all terms to the left:
(15+x/5+x)-(2)=0
Domain of the equation: 5+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-5
x!=-5/1
x!=-5
x∈R
(x+x/5+15)-2=0
We get rid of parentheses
x+x/5+15-2=0
We multiply all the terms by the denominator
x*5+x+15*5-2*5=0
We add all the numbers together, and all the variables
x+x*5+65=0
Wy multiply elements
x+5x+65=0
We add all the numbers together, and all the variables
6x+65=0
We move all terms containing x to the left, all other terms to the right
6x=-65
x=-65/6
x=-10+5/6
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