(15+0.5x)(40-2x)=0

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Solution for (15+0.5x)(40-2x)=0 equation: 



(15+0.5x)(40-2x)=0

We add all the numbers together, and all the variables

(0.5x+15)(-2x+40)=0

We multiply parentheses ..

(+0x^2+0x-30x+600)=0

We get rid of parentheses

0x^2+0x-30x+600=0

We add all the numbers together, and all the variables

x^2-29x+600=0

a = 1; b = -29; c = +600;
Δ = b2-4ac
Δ = -292-4·1·600
Δ = -1559
Delta is less than zero, so there is no solution for the equation

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