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(15)/(x)=(3)/(x-7)
We move all terms to the left:
(15)/(x)-((3)/(x-7))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-7))!=0We calculate fractions
x∈R
15x/(-6x^2)+(-(3*x)/(-6x^2)=0
We calculate terms in parentheses: +(-(3*x)/(-6x^2), so:We get rid of parentheses
-(3*x)/(-6x^2
We add all the numbers together, and all the variables
-(+3x)/(-6x^2
We multiply all the terms by the denominator
-(+3x)
We get rid of parentheses
-3x
Back to the equation:
+(-3x)
15x/(-6x^2)-3x=0
We multiply all the terms by the denominator
-3x*(-6x^2)+15x=0
We multiply parentheses
18x^3+15x=0
We do not support expression: x^3
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