(15)/(p)+(7p-9)/(p+3)=7

Solution for (15)/(p)+(7p-9)/(p+3)=7 equation:

(15)/(p)+(7p-9)/(p+3)=7

We move all terms to the left:

(15)/(p)+(7p-9)/(p+3)-(7)=0


Domain of the equation: p!=0

p∈R



Domain of the equation: (p+3)!=0

We move all terms containing p to the left, all other terms to the right

p!=-3

p∈R


We calculate fractions


(15p+45)/(p^2+3p)+(7p^2-9p)/(p^2+3p)-7=0

We multiply all the terms by the denominator


(15p+45)+(7p^2-9p)-7*(p^2+3p)=0

We multiply parentheses

-7p^2+(15p+45)+(7p^2-9p)-21p=0

We get rid of parentheses

-7p^2+7p^2+15p-9p-21p+45=0

We add all the numbers together, and all the variables

-15p+45=0

We move all terms containing p to the left, all other terms to the right

-15p=-45

p=-45/-15

p=+3