(15(10-0.5y)+4y)+72=180

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Solution for (15(10-0.5y)+4y)+72=180 equation: 



(15(10-0.5y)+4y)+72=180

We move all terms to the left:

(15(10-0.5y)+4y)+72-(180)=0

We add all the numbers together, and all the variables

(15(-0.5y+10)+4y)+72-180=0

We add all the numbers together, and all the variables

(15(-0.5y+10)+4y)-108=0



We calculate terms in parentheses: +(15(-0.5y+10)+4y), so:

15(-0.5y+10)+4y

We add all the numbers together, and all the variables

4y+15(-0.5y+10)

We multiply parentheses

4y+0y+150

We add all the numbers together, and all the variables

5y+150

Back to the equation:

+(5y+150)



We get rid of parentheses

5y+150-108=0

We add all the numbers together, and all the variables

5y+42=0

We move all terms containing y to the left, all other terms to the right

5y=-42

y=-42/5

y=-8+2/5

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