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(14x^2)+6x=76
We move all terms to the left:
(14x^2)+6x-(76)=0
a = 14; b = 6; c = -76;
Δ = b2-4ac
Δ = 62-4·14·(-76)
Δ = 4292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4292}=\sqrt{4*1073}=\sqrt{4}*\sqrt{1073}=2\sqrt{1073}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{1073}}{2*14}=\frac{-6-2\sqrt{1073}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{1073}}{2*14}=\frac{-6+2\sqrt{1073}}{28} $
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