(14x+9)=3+50x+120

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Solution for (14x+9)=3+50x+120 equation: 



(14x+9)=3+50x+120

We move all terms to the left:

(14x+9)-(3+50x+120)=0

We add all the numbers together, and all the variables

(14x+9)-(50x+123)=0

We get rid of parentheses

14x-50x+9-123=0

We add all the numbers together, and all the variables

-36x-114=0

We move all terms containing x to the left, all other terms to the right

-36x=114

x=114/-36

x=-3+1/6

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