(14a+4)(9a+5)=0

Solution for (14a+4)(9a+5)=0 equation:

(14a+4)(9a+5)=0

We multiply parentheses ..

(+126a^2+70a+36a+20)=0

We get rid of parentheses

126a^2+70a+36a+20=0

We add all the numbers together, and all the variables

126a^2+106a+20=0

a = 126; b = 106; c = +20;
Δ = b2-4ac
Δ = 1062-4·126·20
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(106)-34}{2*126}=\frac{-140}{252}
=-5/9
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(106)+34}{2*126}=\frac{-72}{252}
=-2/7
$