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(14/4)y+2/2=3y-5
We move all terms to the left:
(14/4)y+2/2-(3y-5)=0
Domain of the equation: 4)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+14/4)y-(3y-5)+2/2=0
We add all the numbers together, and all the variables
(+14/4)y-(3y-5)+1=0
We multiply parentheses
14y^2-(3y-5)+1=0
We get rid of parentheses
14y^2-3y+5+1=0
We add all the numbers together, and all the variables
14y^2-3y+6=0
a = 14; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·14·6
Δ = -327
Delta is less than zero, so there is no solution for the equation
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