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(14+2x)(24+2x)=704
We move all terms to the left:
(14+2x)(24+2x)-(704)=0
We add all the numbers together, and all the variables
(2x+14)(2x+24)-704=0
We multiply parentheses ..
(+4x^2+48x+28x+336)-704=0
We get rid of parentheses
4x^2+48x+28x+336-704=0
We add all the numbers together, and all the variables
4x^2+76x-368=0
a = 4; b = 76; c = -368;
Δ = b2-4ac
Δ = 762-4·4·(-368)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-108}{2*4}=\frac{-184}{8} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+108}{2*4}=\frac{32}{8} =4 $
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