(13x-5)+(2x+9)=(36-x)

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Solution for (13x-5)+(2x+9)=(36-x) equation: 



(13x-5)+(2x+9)=(36-x)

We move all terms to the left:

(13x-5)+(2x+9)-((36-x))=0

We add all the numbers together, and all the variables

(13x-5)+(2x+9)-((-1x+36))=0

We get rid of parentheses

13x+2x-((-1x+36))-5+9=0



We calculate terms in parentheses: -((-1x+36)), so:

(-1x+36)

We get rid of parentheses

-1x+36

Back to the equation:

-(-1x+36)



We add all the numbers together, and all the variables

15x-(-1x+36)+4=0

We get rid of parentheses

15x+1x-36+4=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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