(13x-19)+132+128=540

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Solution for (13x-19)+132+128=540 equation: 



(13x-19)+132+128=540

We move all terms to the left:

(13x-19)+132+128-(540)=0

We add all the numbers together, and all the variables

(13x-19)-280=0

We get rid of parentheses

13x-19-280=0

We add all the numbers together, and all the variables

13x-299=0

We move all terms containing x to the left, all other terms to the right

13x=299

x=299/13

x=23

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