(13x+45)=(6x+2)=(12x-40)=(19x+3)

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Solution for (13x+45)=(6x+2)=(12x-40)=(19x+3) equation: 



(13x+45)=(6x+2)=(12x-40)=(19x+3)

We move all terms to the left:

(13x+45)-((6x+2))=0

We get rid of parentheses

13x-((6x+2))+45=0



We calculate terms in parentheses: -((6x+2)), so:

(6x+2)

We get rid of parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

13x-6x-2+45=0

We add all the numbers together, and all the variables

7x+43=0

We move all terms containing x to the left, all other terms to the right

7x=-43

x=-43/7

x=-6+1/7

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