(13x+2)+(5x-7)+(3x-4)=17

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Solution for (13x+2)+(5x-7)+(3x-4)=17 equation:



(13x+2)+(5x-7)+(3x-4)=17
We move all terms to the left:
(13x+2)+(5x-7)+(3x-4)-(17)=0
We get rid of parentheses
13x+5x+3x+2-7-4-17=0
We add all the numbers together, and all the variables
21x-26=0
We move all terms containing x to the left, all other terms to the right
21x=26
x=26/21
x=1+5/21

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