(13b-4)-4(3b+1)=2

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Solution for (13b-4)-4(3b+1)=2 equation:


Simplifying
(13b + -4) + -4(3b + 1) = 2

Reorder the terms:
(-4 + 13b) + -4(3b + 1) = 2

Remove parenthesis around (-4 + 13b)
-4 + 13b + -4(3b + 1) = 2

Reorder the terms:
-4 + 13b + -4(1 + 3b) = 2
-4 + 13b + (1 * -4 + 3b * -4) = 2
-4 + 13b + (-4 + -12b) = 2

Reorder the terms:
-4 + -4 + 13b + -12b = 2

Combine like terms: -4 + -4 = -8
-8 + 13b + -12b = 2

Combine like terms: 13b + -12b = 1b
-8 + 1b = 2

Solving
-8 + 1b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 2 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 2 + 8
1b = 2 + 8

Combine like terms: 2 + 8 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10

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