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(130-7x)=(20+3x)
We move all terms to the left:
(130-7x)-((20+3x))=0
We add all the numbers together, and all the variables
(-7x+130)-((3x+20))=0
We get rid of parentheses
-7x-((3x+20))+130=0
We calculate terms in parentheses: -((3x+20)), so:We get rid of parentheses
(3x+20)
We get rid of parentheses
3x+20
Back to the equation:
-(3x+20)
-7x-3x-20+130=0
We add all the numbers together, and all the variables
-10x+110=0
We move all terms containing x to the left, all other terms to the right
-10x=-110
x=-110/-10
x=+11
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