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(13-3/2r)=(1-r)
We move all terms to the left:
(13-3/2r)-((1-r))=0
Domain of the equation: 2r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
(-3/2r+13)-((-1r+1))=0
We get rid of parentheses
-3/2r-((-1r+1))+13=0
We multiply all the terms by the denominator
-(((-1r+1)))*2r+13*2r-3=0
Wy multiply elements
-(((-1r+1)))*2r+26r-3=0
We add all the numbers together, and all the variables
26r-(((-1r+1)))*2r-3=0
We move all terms containing r to the left, all other terms to the right
26r-(((-1r+1)))*2r=3
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