(13+x)(13-x)=()-x2

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Solution for (13+x)(13-x)=()-x2 equation: 



(13+x)(13-x)=()-x2

We move all terms to the left:

(13+x)(13-x)-(()-x2)=0

We add all the numbers together, and all the variables

(x+13)(-1x+13)-(()-x2)=0

We multiply parentheses ..

(-1x^2+13x-13x+169)-(()-x2)=0



We calculate terms in parentheses: -(()-x2), so:

()-x2

determiningTheFunctionDomain
-x2+()

We add all the numbers together, and all the variables

-1x^2

Back to the equation:

-(-1x^2)



We get rid of parentheses

-1x^2+1x^2+13x-13x+169=0

We add all the numbers together, and all the variables

169!=0

There is no solution for this equation

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