(12y-28)/6=4y+3

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Solution for (12y-28)/6=4y+3 equation:



(12y-28)/6=4y+3
We move all terms to the left:
(12y-28)/6-(4y+3)=0
We get rid of parentheses
(12y-28)/6-4y-3=0
We multiply all the terms by the denominator
(12y-28)-4y*6-3*6=0
We add all the numbers together, and all the variables
(12y-28)-4y*6-18=0
Wy multiply elements
(12y-28)-24y-18=0
We get rid of parentheses
12y-24y-28-18=0
We add all the numbers together, and all the variables
-12y-46=0
We move all terms containing y to the left, all other terms to the right
-12y=46
y=46/-12
y=-3+5/6

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