(12y+1)y=35

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Solution for (12y+1)y=35 equation:


Simplifying
(12y + 1) * y = 35

Reorder the terms:
(1 + 12y) * y = 35

Reorder the terms for easier multiplication:
y(1 + 12y) = 35
(1 * y + 12y * y) = 35
(1y + 12y2) = 35

Solving
1y + 12y2 = 35

Solving for variable 'y'.

Reorder the terms:
-35 + 1y + 12y2 = 35 + -35

Combine like terms: 35 + -35 = 0
-35 + 1y + 12y2 = 0

Factor a trinomial.
(-7 + -4y)(5 + -3y) = 0

Subproblem 1

Set the factor '(-7 + -4y)' equal to zero and attempt to solve: Simplifying -7 + -4y = 0 Solving -7 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -4y = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -4y = 0 + 7 -4y = 0 + 7 Combine like terms: 0 + 7 = 7 -4y = 7 Divide each side by '-4'. y = -1.75 Simplifying y = -1.75

Subproblem 2

Set the factor '(5 + -3y)' equal to zero and attempt to solve: Simplifying 5 + -3y = 0 Solving 5 + -3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -3y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -3y = 0 + -5 -3y = 0 + -5 Combine like terms: 0 + -5 = -5 -3y = -5 Divide each side by '-3'. y = 1.666666667 Simplifying y = 1.666666667

Solution

y = {-1.75, 1.666666667}

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