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(12x-5)=(10x+15)
We move all terms to the left:
(12x-5)-((10x+15))=0
We get rid of parentheses
12x-((10x+15))-5=0
We calculate terms in parentheses: -((10x+15)), so:We get rid of parentheses
(10x+15)
We get rid of parentheses
10x+15
Back to the equation:
-(10x+15)
12x-10x-15-5=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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