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(12x-22)=(10x-6)
We move all terms to the left:
(12x-22)-((10x-6))=0
We get rid of parentheses
12x-((10x-6))-22=0
We calculate terms in parentheses: -((10x-6)), so:We get rid of parentheses
(10x-6)
We get rid of parentheses
10x-6
Back to the equation:
-(10x-6)
12x-10x+6-22=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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