(12x+66)=(10x+78)

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Solution for (12x+66)=(10x+78) equation: 



(12x+66)=(10x+78)

We move all terms to the left:

(12x+66)-((10x+78))=0

We get rid of parentheses

12x-((10x+78))+66=0



We calculate terms in parentheses: -((10x+78)), so:

(10x+78)

We get rid of parentheses

10x+78

Back to the equation:

-(10x+78)



We get rid of parentheses

12x-10x-78+66=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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