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(12x+43)=(2x-3)
We move all terms to the left:
(12x+43)-((2x-3))=0
We get rid of parentheses
12x-((2x-3))+43=0
We calculate terms in parentheses: -((2x-3)), so:We get rid of parentheses
(2x-3)
We get rid of parentheses
2x-3
Back to the equation:
-(2x-3)
12x-2x+3+43=0
We add all the numbers together, and all the variables
10x+46=0
We move all terms containing x to the left, all other terms to the right
10x=-46
x=-46/10
x=-4+3/5
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