(12x+4)(3x-1)=0

Solution for (12x+4)(3x-1)=0 equation:

Simplifying
(12x + 4)(3x + -1) = 0

Reorder the terms:
(4 + 12x)(3x + -1) = 0

Reorder the terms:
(4 + 12x)(-1 + 3x) = 0

Multiply (4 + 12x) * (-1 + 3x)
(4(-1 + 3x) + 12x * (-1 + 3x)) = 0
((-1 * 4 + 3x * 4) + 12x * (-1 + 3x)) = 0
((-4 + 12x) + 12x * (-1 + 3x)) = 0
(-4 + 12x + (-1 * 12x + 3x * 12x)) = 0
(-4 + 12x + (-12x + 36x2)) = 0

Combine like terms: 12x + -12x = 0
(-4 + 0 + 36x2) = 0
(-4 + 36x2) = 0

Solving
-4 + 36x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 36x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 36x2 = 0 + 4
36x2 = 0 + 4

Combine like terms: 0 + 4 = 4
36x2 = 4

Divide each side by '36'.
x2 = 0.1111111111

Simplifying
x2 = 0.1111111111

Take the square root of each side:
x = {-0.333333333, 0.333333333}