(12x+28)+(10x+20)=180

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Solution for (12x+28)+(10x+20)=180 equation: 



(12x+28)+(10x+20)=180

We move all terms to the left:

(12x+28)+(10x+20)-(180)=0

We get rid of parentheses

12x+10x+28+20-180=0

We add all the numbers together, and all the variables

22x-132=0

We move all terms containing x to the left, all other terms to the right

22x=132

x=132/22

x=6

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