(12x+18)(1.6-0.2x)=0

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Solution for (12x+18)(1.6-0.2x)=0 equation:



(12x+18)(1.6-0.2x)=0
We add all the numbers together, and all the variables
(12x+18)(-0.2x+1.6)=0
We multiply parentheses ..
(+0x^2+19.2x+0x+28.8)=0
We get rid of parentheses
0x^2+19.2x+0x+28.8=0
We add all the numbers together, and all the variables
x^2+20.2x+28.8=0
a = 1; b = 20.2; c = +28.8;
Δ = b2-4ac
Δ = 20.22-4·1·28.8
Δ = 292.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20.2)-\sqrt{292.84}}{2*1}=\frac{-20.2-\sqrt{292.84}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20.2)+\sqrt{292.84}}{2*1}=\frac{-20.2+\sqrt{292.84}}{2} $

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