(12x+16)+(19x-22)=(24x+15)

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Solution for (12x+16)+(19x-22)=(24x+15) equation: 



(12x+16)+(19x-22)=(24x+15)

We move all terms to the left:

(12x+16)+(19x-22)-((24x+15))=0

We get rid of parentheses

12x+19x-((24x+15))+16-22=0



We calculate terms in parentheses: -((24x+15)), so:

(24x+15)

We get rid of parentheses

24x+15

Back to the equation:

-(24x+15)



We add all the numbers together, and all the variables

31x-(24x+15)-6=0

We get rid of parentheses

31x-24x-15-6=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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