(12x+15)=(3x+78)

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Solution for (12x+15)=(3x+78) equation:



(12x+15)=(3x+78)
We move all terms to the left:
(12x+15)-((3x+78))=0
We get rid of parentheses
12x-((3x+78))+15=0
We calculate terms in parentheses: -((3x+78)), so:
(3x+78)
We get rid of parentheses
3x+78
Back to the equation:
-(3x+78)
We get rid of parentheses
12x-3x-78+15=0
We add all the numbers together, and all the variables
9x-63=0
We move all terms containing x to the left, all other terms to the right
9x=63
x=63/9
x=7

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