(12a)(11a-1)=0

Solution for (12a)(11a-1)=0 equation:

(12a)(11a-1)=0

We multiply parentheses

132a^2-12a=0

a = 132; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·132·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*132}=\frac{0}{264}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*132}=\frac{24}{264}
=1/11
$