(128+29)+(10z-37)=180

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Solution for (128+29)+(10z-37)=180 equation: 



(128+29)+(10z-37)=180

We move all terms to the left:

(128+29)+(10z-37)-(180)=0

determiningTheFunctionDomain
(10z-37)-180+(128+29)=0

We add all the numbers together, and all the variables

(10z-37)-180+157=0

We add all the numbers together, and all the variables

(10z-37)-23=0

We get rid of parentheses

10z-37-23=0

We add all the numbers together, and all the variables

10z-60=0

We move all terms containing z to the left, all other terms to the right

10z=60

z=60/10

z=6

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