(120-2x)2x=1800

Solution for (120-2x)2x=1800 equation:

(120-2x)2x=1800

We move all terms to the left:

(120-2x)2x-(1800)=0

We add all the numbers together, and all the variables

(-2x+120)2x-1800=0

We multiply parentheses

-4x^2+240x-1800=0

a = -4; b = 240; c = -1800;
Δ = b2-4ac
Δ = 2402-4·(-4)·(-1800)
Δ = 28800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28800}=\sqrt{14400*2}=\sqrt{14400}*\sqrt{2}=120\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-120\sqrt{2}}{2*-4}=\frac{-240-120\sqrt{2}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+120\sqrt{2}}{2*-4}=\frac{-240+120\sqrt{2}}{-8}
$