(12/n)+2=(n/4)

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Solution for (12/n)+2=(n/4) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

12/n+2 = n/4 // - n/4

12/n-(n/4)+2 = 0

12*n^-1-1/4*n^1+2*n^0 = 0

(2*n^1-1/4*n^2+12*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^1-1/4*n^2+12*n^0) = 0

n^1

(-1/4)*n^2+2*n+12 = 0

(-1/4)*n^2+2*n+12 = 0

DELTA = 2^2-(4*12*(-1/4))

DELTA = 16

DELTA > 0

n = (16^(1/2)-2)/(2*(-1/4)) or n = (-16^(1/2)-2)/(2*(-1/4))

n = -4 or n = 12

n in { -4, 12} 

n in { -4, 12 }

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