(12/2x-10)-(1/x-5)=7/2

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Solution for (12/2x-10)-(1/x-5)=7/2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(12/2)*x-(1/x)-10+5 = 7/2 // - 7/2

(12/2)*x-(1/x)-(7/2)-10+5 = 0

(12/2)*x-x^-1-7/2-10+5 = 0

6*x^1-1*x^-1-17/2*x^0 = 0

(6*x^2-17/2*x^1-1*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-17/2*x^1-1*x^0) = 0

x^1

6*x^2+(-17/2)*x-1 = 0

6*x^2+(-17/2)*x-1 = 0

DELTA = (-17/2)^2-(-1*4*6)

DELTA = 385/4

DELTA > 0

x = ((385/4)^(1/2)-(-17/2))/(2*6) or x = (-(-17/2)-(385/4)^(1/2))/(2*6)

x = ((385/4)^(1/2)+17/2)/12 or x = (17/2-(385/4)^(1/2))/12

x in { (17/2-(385/4)^(1/2))/12, ((385/4)^(1/2)+17/2)/12}

x in { (17/2-(385/4)^(1/2))/12, ((385/4)^(1/2)+17/2)/12 }

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