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(12-2x)(20-2x)=84
We move all terms to the left:
(12-2x)(20-2x)-(84)=0
We add all the numbers together, and all the variables
(-2x+12)(-2x+20)-84=0
We multiply parentheses ..
(+4x^2-40x-24x+240)-84=0
We get rid of parentheses
4x^2-40x-24x+240-84=0
We add all the numbers together, and all the variables
4x^2-64x+156=0
a = 4; b = -64; c = +156;
Δ = b2-4ac
Δ = -642-4·4·156
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-40}{2*4}=\frac{24}{8} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+40}{2*4}=\frac{104}{8} =13 $
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