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(12-(-3))/3=x
We move all terms to the left:
(12-(-3))/3-(x)=0
We add all the numbers together, and all the variables
-1x+(12-(-3))/3=0
We multiply all the terms by the denominator
-1x*3+(12-(-3))=0
We calculate terms in parentheses: +(12-(-3)), so:Wy multiply elements
12-(-3)
We add all the numbers together, and all the variables
15
Back to the equation:
+(15)
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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