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(12+5y)(5y-5)=159-49
We move all terms to the left:
(12+5y)(5y-5)-(159-49)=0
We add all the numbers together, and all the variables
(5y+12)(5y-5)-110=0
We multiply parentheses ..
(+25y^2-25y+60y-60)-110=0
We get rid of parentheses
25y^2-25y+60y-60-110=0
We add all the numbers together, and all the variables
25y^2+35y-170=0
a = 25; b = 35; c = -170;
Δ = b2-4ac
Δ = 352-4·25·(-170)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-135}{2*25}=\frac{-170}{50} =-3+2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+135}{2*25}=\frac{100}{50} =2 $
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