(12+3i)+(2-5i)=

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Solution for (12+3i)+(2-5i)= equation:


Simplifying
(12 + 3i) + (2 + -5i) = 0

Remove parenthesis around (12 + 3i)
12 + 3i + (2 + -5i) = 0

Remove parenthesis around (2 + -5i)
12 + 3i + 2 + -5i = 0

Reorder the terms:
12 + 2 + 3i + -5i = 0

Combine like terms: 12 + 2 = 14
14 + 3i + -5i = 0

Combine like terms: 3i + -5i = -2i
14 + -2i = 0

Solving
14 + -2i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -2i = 0 + -14

Combine like terms: 14 + -14 = 0
0 + -2i = 0 + -14
-2i = 0 + -14

Combine like terms: 0 + -14 = -14
-2i = -14

Divide each side by '-2'.
i = 7

Simplifying
i = 7

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