If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(12+2x)(8+2x)=36
We move all terms to the left:
(12+2x)(8+2x)-(36)=0
We add all the numbers together, and all the variables
(2x+12)(2x+8)-36=0
We multiply parentheses ..
(+4x^2+16x+24x+96)-36=0
We get rid of parentheses
4x^2+16x+24x+96-36=0
We add all the numbers together, and all the variables
4x^2+40x+60=0
a = 4; b = 40; c = +60;
Δ = b2-4ac
Δ = 402-4·4·60
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-8\sqrt{10}}{2*4}=\frac{-40-8\sqrt{10}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+8\sqrt{10}}{2*4}=\frac{-40+8\sqrt{10}}{8} $
| 25^2+26^2=c^2 | | .4=3^4x | | .6x-11=25 | | 5+2^(3x-1)=12 | | 2+7x=5x-6 | | 3(m-17)=16 | | 5(2-x)=3(4x-8) | | -96=12d | | 2(x+5)=x^2-x+10 | | 3^(x-5)=7^2x | | Y=-x+7x=3 | | r-8.5=-11/12 | | 17g-g=16 | | -8t^2+40t+5=0 | | 10x+6=2(8x-6) | | X/2-x/6+5=x+5 | | 3h,h=1/6 | | 12p=600 | | 5x+25=2x+13 | | -0.4x+3=66x+33 | | 5x=25=2x=13 | | -17g-g=16 | | 12-5(3y+6)=8 | | 2(x-1)=3x-2(1-x) | | |2x-7|=7 | | 5.8x-11.6=23.2 | | 18=2(h-8) | | -39+8x=1-8(1+3x) | | -9x4=81 | | -3(t+2)=-5(t+4)+5 | | 5(2z–3)–3z=3(z+3) | | 1/2(4x-10+5=x-11 |