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(12+2x)(18+2x)-12.18=384
We move all terms to the left:
(12+2x)(18+2x)-12.18-(384)=0
We add all the numbers together, and all the variables
(2x+12)(2x+18)-12.18-384=0
We add all the numbers together, and all the variables
(2x+12)(2x+18)-396.18=0
We multiply parentheses ..
(+4x^2+36x+24x+216)-396.18=0
We get rid of parentheses
4x^2+36x+24x+216-396.18=0
We add all the numbers together, and all the variables
4x^2+60x-180.18=0
a = 4; b = 60; c = -180.18;
Δ = b2-4ac
Δ = 602-4·4·(-180.18)
Δ = 6482.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-\sqrt{6482.88}}{2*4}=\frac{-60-\sqrt{6482.88}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+\sqrt{6482.88}}{2*4}=\frac{-60+\sqrt{6482.88}}{8} $
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